if p+q=12 and pq = 22, then find p2+q2
nogi2k2p57iuf:
its 100
Answers
Answered by
64
=>p+ q = 12, pq = 22
=> (p+q)^2 = p^2+q^2 + 2pq
=> (p+q)^2 -2pq = p^2+ q^2
=>p^2 +q^2 = (12)^2 -2(22)
=> p^2 + q^2 = 144 - 44 = 100
=> p^2+q^2=100
hope u like this.
=> (p+q)^2 = p^2+q^2 + 2pq
=> (p+q)^2 -2pq = p^2+ q^2
=>p^2 +q^2 = (12)^2 -2(22)
=> p^2 + q^2 = 144 - 44 = 100
=> p^2+q^2=100
hope u like this.
Answered by
51
USING IDENTITY=(a+b)^2=a^2+2ab+b^2
a=p,b=q
(a+b)^2=a^2+2ab+b^2
(p+q)^2=p^2+2×p×q+q^2
12^2=p^2+q^2+44
144=p^2+q^2+44
p^2+q^2=144-44=100
HOPE THIS WILL HELP U
a=p,b=q
(a+b)^2=a^2+2ab+b^2
(p+q)^2=p^2+2×p×q+q^2
12^2=p^2+q^2+44
144=p^2+q^2+44
p^2+q^2=144-44=100
HOPE THIS WILL HELP U
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