Question

if p+q = √13 and p-q = √7 , find the value of pq(p^2 + q^2)

Answer 1

hello!
#ur Ans
_________

==> p+q = √13..........(1)

==> p-q = √7...........(2)


Now add the equation (1) & (2)

==> 2p = √13 +√7

==>p = (√13+√7)/2

put the Value of P in equation 1

==> (√13+√7)/2 +q = √13


Taking LCM

==> q = (2√13 -√13-√7)/2

==> q = √13-√7/2

Now put the Value of p & q
in pq(p^2 +q^2)

U get the Ans

Answer 2

Step-by-step explanation:

ANSWER ✍️

_________

==> p+q = √13..(1)

==> p-q = √7..(2)

Now add the equation (1) & (2)

==> 2p = √13 +√7

==>p = (√13+√7)/2

put the Value of P in equation 1

==> (√13+√7)/2 +q = √13

Taking LCM

==> q = (2√13 -√13-√7)/2

==> q = √13-√7/2

Now put the Value of p & q

in pq(p^2 +q^2)

hope this helps you!!