Question

If p+q=√13and p-q=√5 then what will the value of p×q=?

Answer 1

Answer:

2

Step-by-step explanation:

To find each value, we'll use elimination method.

The values, are $p=\frac{\sqrt{13} +\sqrt{5} }{2}$ $q=\frac{\sqrt{13} -\sqrt{5} }{2}$

Multiplication of p×q

$\frac{\sqrt{13} +\sqrt{5} }{2}\times \frac{\sqrt{13} -\sqrt{5} }{2}=\frac{13-5}{4} =2$

The answer is 2.

Answer 2

Answer:

p*q = 2

Step-by-step explanation:

since p+q  = root13

now square on bot sides so we get

p^2 + q^2 + 2*p*q = 13

in same way do to p-q = root5 , we get

p^2 + q^2 - 2*p*q =5

now subtract bot we get

4*p*q = 8

so p*q = 2