Question

If p q = 18 & Pt q = 11 then vale of p & q are​

Answer 1

${\tt{\green{\underline{\underline{\huge{Answer}}}}}}$

If p+q and pq are known then quadratic equation corresponding to roots as p and q is given by,

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$\sf\green{ ⇒x²-(p+q)\: x+pq\:= 0}$

⇒x²-11x + 18 =0 , substitute the given values

⇒x² -9x -2x +18 =0 ,split the middle term

⇒( x² - 9x ) + ( -2x +18 )=0, group pair of terms

⇒x(x−9)−2(x−9)=0, factor each binomials

⇒(x−9)(x−2)=0, factor out common factor

$\sf\red{ ⇒x=9 \:or \:x=2, \:set \:each\: factor\: to \:0}$

Hence p and q are 9 and 2

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Hope it helps you