Math, asked by AmanprasadA624, 9 months ago

If p/q = (2/3)^2x(1/3)^-4 find the value of (p/q)^-2

Answers

Answered by rishabhpy3
3

Answer:

(p/q)^-2 = 1/1296

Step-by-step explanation:

p/q = (2/3)^2 * 1/3 ^ -4

=  (2/3)^2 * (3)^ 4

= (2)^2 * (3)^ 2

= 4 * 9 = 36

p/q = 36;

(p/q)-2 = (36)^-2

(p/q)-2 = 1/(36)^2

(p/q)-2 = 1/1296

Answered by Asanhmr
1

Answer: (p/q)^-2= 1/1296

Step-by-step explanation:

p/q = (2/3)^2x(1/3)^-4= 2^2/3^(2-4)

=2^2/3^(-2)

= 2^2× 3^2= (2×3)^2= 6^2= 36

(p/q)^-2=(6^2)^-2= 6^(-2×2) = 6^-4

= 1/6^4= 1/1296

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