If p/q=(2/3)³÷(2/3)⁰, find the value of (p/q)²...
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Given that
p(x)=ax
3
+bx
2
+cx+d .........(1) where a
=0 is a cubic polynomial
And p,q,r are the zeroes of the polynomial p(x)
We all know that
p+q+r=
a
−b
= Sum of the roots
pq+qr+rp=
a
c
= Product of roots taken two at a time
pqr=
a
−d
= product of roots
In the Question
p
1
+
q
1
+
r
1
=
pqr
pq+qr+rp
=
a
−d
a
c
=
d
−c
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