Question

if p+q=23 and p-q=7 then find p^2+q^2​

Answer 1

Step-by-step explanation:

Assume (p/q)=x

So. (p/q)+(q/p)=2

i.e., x+(1/x)=2

x^2 + 1 = 2x

x^2 -2x +1 =0

x^2-x-x+1=0

x(x-1)-1(x-1)=0

(x-1)(x-1)=0

(x-1)=0 or (x-1)=0

x=1 and x=1

･ﾟ･ (p/q)=(q/p)=1

Consider ,

(p/q)^23+(q/p)^7

=(1)^27+(1)^7

=1+1

=2

Thank you

Answer 2

Step-by-step explanation:

what is this you explain this question