Question

if p/q=(3/2) ^-2÷(6/7) ^°find the value of (p/q) ^-3​

Answer 1

Answer:

given that

$\frac{p}{q } = ( \frac{3}{2} ) ^{2} \div ( \frac{6}{7} ) ^{0}$

so now finding the vlaue of p/q

$\frac{p}{q} = \frac{9}{4} \times \frac{1}{1}$

as n^0 = 1

$\frac{p}{q} = \frac{9}{4}$

now finding the value of

$(\frac{p}{q}) ^{ - 3} \\ = (\frac{9}{4} ) ^{ - 3} \\ = (\frac{4}{9})^{ 3} \\ = \frac{64}{729}$

and hence the answer 64/729

tips:

• do the calculation very carefully
• try to do it in a most easy way
• try to maintain the copy neat and for flow