Math, asked by priyalahiri2807, 11 months ago

If p:q = 3: 4 and x:y = 7:5 then (10px - 6qy/5qx - 4py) = ?

Answers

Answered by hemalathakalyani
1

Answer:1.125

Step-by-step explanation:

p/q = 3/4 ;   x/y = 7/5

4p = 3q;       5x = 7y

(10px - 6qy)/(5qx - 4py) = 2*(5px - 3qy)/(5qx - 4py)

                                      = 2*(7py - 4py) / (7qy - 3qy)

                                      = 2*(3py)/(4qy)

                                      = 3p/2q

                                       =3*(3p)/3*(2q)

                                        = 9p/8p

                                       =9/8

                                      =1.125

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