IF P.Q=√3 (magnitude of PxQ), then the angle between vector A and B is
(1) 45°
(2) 30°
(3) 60°
(4) 90°
Answers
Answered by
2
Your answer is :-
Given, P.Q = √3
as we know
P.Q = PQcos∅
•°• PQcos∅ = √3 ...(1)
also give
|P×Q| = √3
=> PQsin∅ = √3 (as we know P×Q = PQsin∅) ......(2)
from (1) & (2)
PQcos ∅= PQsin∅
=> tan∅ = 1
=> ∅ = 45°
Pranav017:
Thanks very much mam
Answered by
0
Answer:
Angle between both vectors is 45°
Step-by-step explanation:
Given, P.Q = √3
As we know, dot product of two vectors is P.Q= |P||Q| cosθ
∴ |P||Q| cosθ= √3 .......(1)
Where θ is angle between both vectors P and Q.
Also given |P×Q| = √3
As we know, dot product of two vectors is P×Q = |P||Q| sinθ
|P||Q| sinθ = √3 .........(2)
from equation (1) & (2)
|P||Q| cosθ = |P||Q| sinθ
tanθ = 1
θ = 45°
∴Angle between both vectors is 45°
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