If p + q = 4 and p2 + q2 = 7, then the value of p q is
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Answered by
1
Answer:
ANSWER
p + q = 4
and p
2
+ q
2
= 7
(p + q)
2
= (4)
2
= 16
⇒ p
2
+ q
2
+ 2pq = 16
⇒ 7 + 2pq = 16
⇒ 2pq = 9
pq =
2
9
Answered by
30
Given :-
p + q = 4
p^2 + q^2 = 7
To Find :-
The value of p and q and pq
Solution :-
Here we know,
p + q = 4........eq( 1)
p^2 + q^2 = 7
Using identity a^2 + b^2 = ( a + b) ( a - b)
( p + q) ( p - q ) = 7
4 + ( p - q) = 7
( From eq(1) the value of p+ q= 4)
( p - q) = 7 - 4
(p - q ) = 3 .........eq( 2 )
Solve by Elimination method,
p + q = 4
p - q = 3
p - 0 = 1
p = 1........eq( 3)
Subsitute eq( 3) in eq( 1)
p + q = 4
1 + q = 4
q = 4 - 1
q = 3
Now , The value of pq
pq = 1 * 3
pq = 3
3 is your answer mate
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