Math, asked by rpmprmnk, 9 months ago

if (p/q)^(4m-1)=(q/p)^(2m-3), then the value of m=

Answers

Answered by Gangothrigangothri
0

Answer:

2/3

Step-by-step explanation:

(p^(4m-1))/(q^(4m-1))=(q^(2m-3))/(p^(2m-3))

(p^4m*p^-1)/(q^4m*q^-1)=(q^2m*q^-3)/(p^2m*p^-3)

(p^4m*q)/(q^4m*p)=(q^2m*p^3)/(p^2m*q^3)

p^4m*p^2m*q^4=q^4m*q^2m*p^4

p^6m*q^4=q^6m*p^4

p^6m/q^6m=p^4/q^4

equating the powers, we get, 6m=4

m=4/6

m=2/3

hope this is helpful...

Answered by anildeny
0

Answer: 1 : 16

Step-by-step explanation:

linear momentum of P = mv

linear momentum of Q = (4m)(4v) = 16mv

ratio of momentum = mv/16mv = 1/16

ratio of momentum of P and Q = 1 : 16

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