Math, asked by karan3966, 1 year ago

if (p+q)=7 and pq=12 evaluate
p²+q²

amarkumar6130: 25

Answers

Answered by fika1233

p²+q²=(p+q)²-2pq
=7²-2×12
=49-24
=25
ok

leany: possible values:4and 3 then 4 plus 3=7,4×3=12 hence 4 power 2 +3power 2 gives 16+9=25

fika1233: how

fika1233: plz explain

fika1233: ok

fika1233: i got it

5T4rL0Rd: ur answer is not explained properly

fika1233: thanks

Answered by 5T4rL0Rd

hi friend hope this answer helps you

given: p+q=7 , pq=12

find: p² + q²

identity used: (a+b)² = a²+2ab+b²

answer: (p+q)² = p² + 2pq + q²

(7)² = p² + q² + 2×12

49 = p² + q² + 24

49 - 24 = p² + q²

25 = p² + q²

therefore p²+q² = 25

if this helped you pleas mark as the brainliest !!

5T4rL0Rd: thank you so much for marking the ans as the brainliest

5T4rL0Rd: : ) !!!!

karan3966: wellcome

5T4rL0Rd: who reported my question?

karan3966: i don't know

5T4rL0Rd: its pk

5T4rL0Rd: ok

karan3966: thanks for ans. well

5T4rL0Rd: thank you for the appreciation

5T4rL0Rd: : )

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