Math, asked by Namami133, 2 days ago

If p + q = 8 and pq = 6 , find the value of ^2+q^2?

Answers

Answered by vatsamugdha300282
2

Answer:

(p+q)^2 = p^2 + q^2 + 2pq

p^2+q^2 = (p+q)^2- 2pq

Given that,

p+q = 8 and pq=6

p^2+q^2 = 8^2 - 2×6= 64 -12 = 52

p^2+q^2=52

Answered by srinivasraomail49
1

Answer:

we have ,

Step-by-step explanation:

p+q=8,pq=6,so using (a+b)^2 formula we get p^2+q^2=(p+q)^2-2pq=64-12=52 hope it helps you please mark me as brainliest

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