Math, asked by raunakeye, 2 months ago

If p + q = 8 and pq = 6 , find the value of p^2+q^2 .​

Answers

Answered by Sristi199
2

Answer:

Using the identity (a+b)

3

=a

3

+b

3

+3ab(a+b), we can write

(p+q)

3

=p

3

+q

3

+3pq(p+q)

It is given that p+q=5 and pq=6, therefore,

(p+q)

3

=p

3

+q

3

+3pq(p+q)

⇒(5)

3

=p

3

+q

3

+(3×6)(5)

⇒125=p

3

+q

3

+(18×5)

⇒125=p

3

+q

3

+90

⇒p

3

+q

3

=125−90

⇒p

3

+q

3

=35

Hence, p

3

+q

3

=35.

Answered by y2krahulsingh
1

Answer:

Given,

p + q = 8 & pq = 6 ; p^2 + q^2 = ?

A.T.Q,

(p + q) = 8

squaring both side

(p + q)^ 2 = (8)^2

or, p^2 + 2pq + q^2 = 64

or, p^2 + 2×6 + q^2 = 64

or, p^2 + 12 + q^2 = 64

or, p^2 + q^2 = 64 - 12

or, p^2 + q^2 = 52 (ans.)

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