Question

if p-q =-8,pq=-12 then find the value of p cube -q cube
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Answer 1

Answer:

[using identity, (a-b)³=a³-b³-3ab(a+b) ](p-q)³=p³- q³-3pq(p-q)

(-8)³=p³-q³-3(-12) (-8)

-512=p³-q³-288

p³-q³=288-512

p³-q³=-224

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

p-q= -8,. pq= -12

p^2+q^2=(p-q)^2+2pq

=(-8)^2+2(-12)

=64-24=40

p^3-q^3=(p-q)(p^2+pq+q^2)

=(-8)(40-12)

=(-8)28= -224