Question

if p/q=a then p square + q square / p square - q square =​

Answer 1

yr answer in the attachment

Answer 2

The value of $\frac{p^2 + q^2}{p^2-q^2}$ = -1 when we take the p = aq substituting the p values in the expression we get -1.

Given that,

$\frac{p}{q}$ = a

We have to find the value of $\frac{p^2 + q^2}{p^2-q^2}$

We know that,

What are variables?

A variable is an entity that can take many different values. Anything that can change can be considered a variable. For example, age can be considered a variable. This is because age can take different values ​​for different people or even for the same person at different times.

So, here variables are p and q

Take

$\frac{p}{q}$ = a

p = aq

$\frac{(aq)^2 + q^2}{(aq)^2-q^2}$

$\frac{q^2(a^2 + 1)}{q^2(a^2-1)}$

$\frac{a^2+1}{a^2-1}$

$\frac{(a+1)^2-2a}{(a-1)(a+1)}$

$\frac{(a+1)-2a}{(a-1)}$

$\frac{1-a}{a-1}$

$-\frac{a-1}{a-1}$

-1

Therefore, the value of $\frac{p^2 + q^2}{p^2-q^2}$ = -1

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