If p,q and r are in AP then find the sum of r and p in terms of 'q'.
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Step-by-step explanation:
Given p,q,r are in AP
∴q−p=r−q (distance between p & q is equal to distance between q & r)
∴2q=r+p......(1)
LHS=(p+2q−r)(2q+r−p)(r+p−q)
=(p+r+p−r)(r+p+r−p)(r+p−q) [∵ from eqn (1) sub for 2q]
=2p.2r(2q−q) (from eqn (1))
=4pqr
=RHS
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