Question

If p, q and r are the zeroes of the cubic polynomial x^3 - 6x^2 - x + 30 then the product of the zeroes i .e. p.q.r. is

Answer 1

Given :  p, q, r are the zeroes of the cubic polynomial x³ – 6 x² – x + 30  

To Find : values of p+q+r and   pqr.

Solution:

cubic polynomial x³ – 6 x² – x + 30  

p, q, r are the zeroes

Sum of zeroes  =  - ( - 6) / 1  = 6

Hence p + q + r = 6

Product of zeroes  =     -30/ 1 = -30

=> pqr =   -30

Another method :

x³ – 6 x² – x + 30  

= (x - 3)(x²  - 3x  - 10)

= (x - 3)(x - 5)(x + 2)

p , q and r  are    - 2 ,  3 ,  5  

p + q + r = - 2 + 3 + 5 = 6

pqr = (-2)(3)(5)  = - 30

Learn More :

Find a quadratic polynomial whose zeroes are 1/2 , 4 - Brainly.in

brainly.in/question/16158030

Find the quadratic polynomial whose zeroes are log 1000, log0.01*0.1

brainly.in/question/18047168

brainly.in/question/18973744