If p,q are 0s of polynomial f(x)=2x²-7x+3 find the value of p²+q²
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Answer:-
Given Polynomial => 2x² - 7x + 3
Let , a = 2 ; b = - 7 and c = 3
We know that,
Sum of the roots = - b/a
→ p + q = -(-7/2)
→ p + q = 7/2 -- equation (1)
Product of the roots = c/a
→ pq = 3/2 -- equation (2)
We know,
(a + b)² = a² + b² + 2ab
→ a² + b² = (a + b)² - 2ab
→ p² + q² = (p + q)² - 2ab
Putting the values from equation (1) & (2) we get,
→ p² + q² = (7/2)² - 2(3/2)
→ p² + q² = 49/4 - 6/2
Taking LCM in RHS we get,
→ p² + q² = (49 - 12)/4
→ p² + q² = 37/4
Hence, the value of p² + q² is 37/4.
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