Question

If P,Q are the points of trisection of A=(1,-2) B=(-5,6),then P,Q=

Answer 1

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Given :

• Points are P(1 , -2) and Q(-5 , 6)

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To Find :

• Value of PQ (Distance between P and Q)

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Solution :

Here,

• x1 = 1
• x2 = -5
• y1 = -2
• y2 = 6

Now, use distance Formula :

$\large{\boxed{\sf{|PQ| \: = \: \sqrt{(x_2 \: - \: x_1)^2 \: (y_2 \: - \: y_1)^2}}}} \\ \\ \rightarrow {\sf{|PQ| \: = \: \sqrt{ \big(1 \: - \: (-5) \big)^2 \: + \: \big( 6 \: - \: (-2) \big) ^2}}} \\ \\ \rightarrow {\sf{|PQ| \: = \: \sqrt{(5 \: + \: 1)^2 \: + \: (6 \: + \: 2)^2}}} \\ \\ \rightarrow {\sf{|PQ| \: = \: \sqrt{(6)^2 \: + \: (8)^2}}} \\ \\ \rightarrow {\sf{|PQ| \: = \: \sqrt{36 \: + \: 64}}} \\ \\ \rightarrow {\sf{|PQ| \: = \: \sqrt{100}}} \\ \\ \rightarrow {\sf{PQ \: = \: 10 \: units}}$