Question

if p,q are the roots of x²+bx+c=0,show thatb,c are the roots of x²+(p+q-pq)x-pq(p+q)=0​

Answer 1

Answer:

p+q=-b

pq=c

put the above values in eq 2

eq

x²+(-b-c)x-(-bc)=0

x²-(b+c)x+bc=0

we know that

x²-(root1+root2)x+(root1×root2)=0

hence proved