if p,q are the roots of x²+bx+c=0,show thatb,c are the roots of x²+(p+q-pq)x-pq(p+q)=0
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Answer:
p+q=-b
pq=c
put the above values in eq 2
eq
x²+(-b-c)x-(-bc)=0
x²-(b+c)x+bc=0
we know that
x²-(root1+root2)x+(root1×root2)=0
hence proved
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