Question

if p,q are the zeroes of x²+ax+c then value of p³+q³-3ac?​

Answer 1

Step-by-step explanation:

p,q are the zeroes of x²+ax+c

so,

p+q= -a

pq= c

now,

p³+q³-3ac

(p+q)(p²+q²-pq)-3ac

(p+q){(p+q)²-2pq-pq}-3ac

(p+q){(p+q)²-3pq}-3ac

-a{(-a)²-3c}-3ac

-a(a²-3c)-3ac

-a³+3ac-3ac

-a³

#666