Question

If p,q are the zeros of 2x^2-7x+3 find p^2-q^2​

Answer 1

Answer:

2x^2-7x+3

p+q=7/2

pq=3/2

(p-q) ²=(p+q) ²-4pq=49/4 -4×3/2

=49/4 -6=25/4

p-q=√(25/4) =5/2

p²-q²=(p+q) (p-q) =7/2×5/2=35/4

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