if p,q are zeroes of polynimal f(x)=2x²-7x+3 , find the value of p²+q².
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Step-by-step explanation:
p+q=-(-7)/2
=7/2
pq=3/2
now,
p²+q²=(p+q)²-2pq
=(7/2)²-2(3/2)
=49/4-3
=37/4
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