Question

If p , q are zeroes of polynomial 2x^2 - x - 3 then form a polynomial whose zeroes are 2p and 2q.​

Answer 1

Answer:

x²-x-6

Step-by-step explanation:

Let zeroes be p and q

$2 {x}^{2} - x - 3 = 0\\ 2 {x}^{2} + 2x - 3x - 3 = 0\\ 2x(x + 1) - 3(x + 1) = 0$

$(2x - 3)(x + 1) = 0 \\ 2x - 3 = 0 \: \: \: \: \: \: \: \: \: \: x + 1 = 0 \\ x = \frac{3}{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - 1 \\ p = \frac{3}{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: q = - 1$

p'=2p. q'=2q

$2p = \frac{2 \times 3}{2} \: \: \: \: \: \: \: \: \: \: \: 2q = - 1 \times 2$

p'=3. q=-2

p(x)=x²-(p'+q')x+p'.q'

p(x)=x²-(3-2)x+(3)(-2)

p(x)=x²-x-6

Hope it helps

Plz mark as brainlist