Question

if p,q are zeros of 2x²-6x+3then find the values of (p³+q³)-3pq(p²+q²)-3pq (p+q) pls say fast mam /sir​

Answer 1

Answer:

that is your answer go ahead

Answer 2

Answer:

STEP BY STEP EXPLANATION

2x2−6x+3 is the given equation

p and q are the zeroes therefore

p + q = -(-6)/2=3

and pq = 3/2

p^{3}+q^3 -3pq(p^2+q^2)-

3pq(p+q)p3+q3−3pq(p2+q2)−3pq(p+q) =

[(p+q)^3 - 3pq(p+q)] - 3pq[(p+q)^2 - 2pq]

-3pq(p+q)[(p+q)3−3pq(p+q)]

−3pq[(p+q)2−2pq]−3pq(p+q)

substituting the values of (p +q) and (pq)

substituting the values of (p +q) and (pq)we get

-27 as the answer

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