Question

if p-q equal to 1 and PQ is equals to 6 then the value of p ki power 3 e minus Q ki power 3 is​

Answer 1

Given,

p-q=1

p×q=6

We know that,

The factors of 6 =1,2,3,6

If we take p=3,q=2

Then p-q=1

3-2=1

1=1

☆LHS=RHS

Therefore p=3,q=2

Value of p³-q³=

$p ^{3} - {q}^{3} = {3}^{3} - {2}^{3} \\ = 27 - 8 \\ = 19$

Hence the value of p³-q³ is 19