If p + q equal to 2 then the value of P cube+ q cube + 6 p square + 5 q square + 6 PQ is?
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Please find below the solution to the asked query:
We have p+q=2NowS=p3+q3+6p2+5q2+6pqNow(a+b)3=a3+b3+3ab(a+b)⇒a3+b3=(a+b)3−3ab(a+b)⇒S=(p+q)3−3pq(p+q)+6p2+5q2+6pq=(2)3−3pq(2)+6p2+5q2+6pq=8−6pq+6p2+5q2+6pq=6p2+5q2+8⇒p3+q3+6p2+5q2+6pq=6p2+5q2+8More information is needed to further simplify it
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