if p/q form of 0.38 is m/n then value of m^2+n^2/mn
Answers
Answer:
Aim:
The fractional form of the given decimal number 0.38 is \frac{m}{n}
n
m
, where we have to find the value of (m+n)(m+n)
Procedure of solving:
We must convert the given decimal number into the fractional form. For example, let 0.010.01 be a decimal number. So, the \frac{p}{q}
q
p
form of 0.010.01 will be \frac{1}{100}
100
1
After finding the \frac{p}{q}
q
p
form of the given decimal number 0.380.38 , we need to reduce the fraction.
By finding the values of mm and nn , we can find the sum of mm and nn .
Solution:
0.38=\frac{m}{n}0.38=
n
m
0.38=\frac{38}{100}0.38=
100
38
\frac{m}{n}=\frac{38}{100}
n
m
=
100
38
\frac{m}{n}=\frac{19}{50}
n
m
=
50
19
∴ The value of mm and nn are 1919 and 5050 respectively.
(m+n)=19+50(m+n)=19+50
(m+n)=69(m+n)=69
∴ The sum of mm and nn is 6969 .
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