Math, asked by sriramavasan50, 8 months ago

if p:q is the sub duplicate ratio of p-x^2: q-x^2 then X^2 is

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Answered by Shailesh183816
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Answered by Anonymous
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The sub-duplicate ratio of m:nm:n is m−−√:n−−√.m:n.

It is given that p:qp:q is the sub-duplicate ratio of p−x2:q−x2.p−x2:q−x2.

⇒p−x2√q−x2√=pq⇒p−x2q−x2=p2q2.⇒p−x2q−x2=pq⇒p−x2q−x2=p2q2.

⇒q2(p−x2)=p2(q−x2)⇒pq2−q2x2=qp2−p2x2.⇒q2(p−x2)=p2(q−x2)⇒pq2−q2x2=qp2−p2x2.

⇒p2x2−q2x2=qp2−pq2⇒x2(p2−q2)=pq(p−q).⇒p2x2−q2x2=qp2−pq2⇒x2(p2−q2)=pq(p−q).

⇒x2=pq(p−q)p2−q2=pqp+q⋯(⇒x2=pq(p−q)p2−q2=pqp+q⋯(provided p≠q).p≠q).

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