Math, asked by Alice1256, 1 year ago

If p+q+r =0 for all positions of the moving straight line px+qy+r =0, show that the line always passes through a fixed point. Find the coordinate of that point.

Answers

Answered by parisakura98pari
1
p+q+r=0                and line≡ px+qy +r = 0

then for point (1,1)  p+q+r=0

so that fixed point is (1,1) .

hope my ans is correct

Alice1256: Can you explain a bit more
parisakura98pari: Well actually there's a method to solve it . I'm trying to solve it. You please wait.
parisakura98pari: In the question the condition is already given that p+q+r = 0.
parisakura98pari: Now from hit and trial method, we find (1,1) satisfy this conditions .
parisakura98pari: Therefore (1,1) is that fixed point.
parisakura98pari: In case the condition would have been 2p + 3q+r = 0, we would have perceived that (2,3) is that fixed point.
parisakura98pari: I'm sorry to make you wait.Hope you understand my elucidation .
parisakura98pari: Thank you very much.
Answered by aaravbhardwaj12
1
p+q+r=0
line=px+qy+r=0

Point (+,+) p+q+r=0
So we can take 1,1 as point


here answer is 1,1

Alice1256: Can you explain a bit more
aaravbhardwaj12: Ohk
aaravbhardwaj12: I will explain it tomorrow
aaravbhardwaj12: Just wait
Alice1256: Thanks
aaravbhardwaj12: Ur welcome
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