Question

If p+q+r+16 and pq+qr+rp=25 find p2 + q2 + r2

Answer 1

so, your answer is 206

Answer 2

As per the data given in the above question.

We have to find out the value of

$p²+q²+r²$

Step-by-step explanation:

Given,

$p+q+r = 16$

$pq+qr+rp=25$

According to the Identity,

$(p+q+r)²= \\ p²+q²+r²+2pq+2qr+2rp$

Step 1:

Arrange the above identity for proper calculation

$(p+q+r)²= \\ p²+q²+r²+2(pq+qr+rp)$

Put the values given in the question,

$(16)²= p²+q²+r²+2(25)$

$16 \times 16= p²+q²+r²+50$

$256= p²+q²+r²+50$

$256 - 50= p²+q²+r²$

or

$p²+q²+r² = 256 - 50$

$p²+q²+r² = 206$

Hence ,

The value of p²+q²+r² = 206

Project code #SPJ3

#NOTE

Question should be written in the form

If p+q+r+16 and pq+qr+rp=25 find p²+ q²+ r².