Question

If p+q+r=9 and pq+qr+pr=26 then p2+q2+r2 =

Answer 1

Hari Om...!

Your solution goes like this :-


Given,

pq + qr + pr = 26.

and,

p + q + r = 9.
${(p + q + r)}^{2} = {p}^{2} + {q}^{2} + {r}^{2} + 2pq + 2qr + 2pr \\ = > {9}^{2} = {p}^{2} + {q}^{2} + {r}^{2} + 2(pq + qr + pr) \\ = > 81 = {p}^{2} + {q}^{2} + {r}^{2} + 2(26) \\ = > 81 - 52 = {p}^{2} + {q}^{2} + {r}^{2} = 29$

Thus, p² + q² + r² = 29 answer.

Regards

KSHITIJ

Answer 2

Heya Mate !!!

Here's Your Answer :- 29.

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Step By Step Explanation ;-
=======================

Given that ; pq + qr + pr = 26.
and p + q + r = 9.

=> (p+q+r)^2 = p^2 + q^2 + r^2 + 2qr + 2pq

=> 9^2 = p^2 + q^2 + r^2 + 2 { pq + qr + pr }

=> 81 = p^2 + q^2 + r^2 + 2{26}

=> 81 - 52 = p^2 + q^2 + r^2 = 29

Hence , p^2 + q^2 + r^2 = 29 ( Answer )

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