Question

If P-Q-R and d(P,Q) =3.4, d(Q,R)=5.7 then d(P,R) = ? Answer the question.

Answer 1

Given:P-Q-R
d(PQ)=3.4
d(QR)=5.7
To find:d(PR)
Solution:d(PR)=d(PQ)+d(QR)
d(PR)=3.4+5.7
d(PR)=9.1

Answer 2

Hello dear,

● Answer -
d(P,R) = 9.1 units

● Explanation -
# Given -
d(P,Q) = 3.4
d(Q,R) = 5.7

# Solution -
Given that points P, Q & R are collinear.

Therefore,
d(P,R) = d(P,Q) + d(Q,R)
d(P,R) = 3.4 + 5.7
d(P,R) = 9.1 units


Therefore, distance between point P & R is 9.1 units.


Hope this helped you. Thanks for asking dear.