if p+q =r and p-q =s prove that r2+s2=2(p2+q2).
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Given:
p + q = r and p - q = s
To Prove:
r² + s²=2(p²+q²)
Solution:
As given,
p + q = r ------ (1)
p - q = s------- (2)
now squaring and adding both equation,
⇒ (p + q)² + (p - q)² = r² + s²
⇒ p² + q² + 2pq + p² + q² - 2pq = r² + s²
⇒ p² + q² + p² + q² = r² + s²
⇒ 2p² + 2q² = r² + s²
⇒ 2( p² + q²) = r² + s²
Hence, proved.
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