If p, q, r are in A.P., then p^{3} + r^{3} -8q^{3} is
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Since, p,q and r are in AP,
(p+r)/2
p^3 + r^3 - 8q^3
p^3 + r^3 - 8[(p+r)/2]^3
p^3 + r^3 - 8[p^3 + r^3 + 3p2r + 3r2p]/8
p^3 + r^3 - p^3 - r^3 - 3p2r - 3r2p
-[3p2r + 3r2p]
-3pr(p + r)
-3pr(2q) (p+r = 2q)
-6pqr
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