Question

if P Q R are in AP x y z are in GP then x power 2 minus ki power r minus p Z ki power p minus q is equal to

Answer 1

Thank you for asking this question. Here is your answer:

p,q,r are in AP so 2q = p+r

and x,y,z are in gp so y² = xz

Now x^q-r y^r-p z^p-q = x^(p+r/2-r) y^r-p z^(p-(p-r)/2)

= x^(p-r/2) . y^r-p z^(p-r/2)

= x^(p-r/2) . (xz)^(r-p)/2 z^(p-r/2)

= x^(p-r/2) . x^(r-p/2) z^(r-p/2) z^(p-r/2)

= x^0 z^0

= 1

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