if p,q,r are in gp then show that logp,logq,logr are in ap
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Since p, q and r are in GP,
b/a = c/b
=> b² = ac
logarithm on both sides,
=> log(b²) = log(ac)
=> 2log(b) = log(a) + log(c)
=> log(b) + log(b) = log(a) + log(c)
=> log(b) - log(a) = log(c) - log(b)
Since the difference between the consecutive terms is equal, these logarithms are in AP
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1
Is it correct.......
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