Question

If p q r are the distances covered by a body moving with a uniform acceleration during.....​

Answer 1

Answer:

Let 'u' be the initial velocity of the particle and A be its uniform acceleration. Using this relation.

Dth= u+a/2(2n-1) we have

   a =u+A/2(2l-1) ....(i)

   b =u+A/2(2m-1) ...(ii)

   c =u+A/2(2n-1) ....(iii)

Subtracting (iii) from (ii) we have,

b-c=A/2(2m-2n)= A(m-n)

or a(m-n)=a(b-c)/A = (ab-ac)/A .. (iv)

Subtracting (i) from (iii) we have,

c -a = A/2 (2n - 2l) = A (n -l)

or, b(n - l) = b(c - a)/A = (bc - ab)/A ....(v)

Subtracting (ii) from (i) we have,

( a - b) = A/2 (2l - 2m) = A(l - m)

or, c(l - m ) = c(a - b)/A = (ac -bc)/A ....(vi)

Adding (iv), (v) and (vi) we have,

a(m- n) + b(n - l) + c(l -m)

    ={(ab-ac)/A} + {(bc-ab)/A} + {(ac-bc)/A} = 0

Explanation: