Question

If p, q, r are the zeroes of the cubic polynomial
X 3 – 6 x 2 – x + 30 then find the values of p+q+r and pqr.

Answer 1

Answer

P+Q+R= 6

PQR= 30

Step-by-step explanation:

Answer 2

Given :  p, q, r are the zeroes of the cubic polynomial x³ – 6 x² – x + 30  

To Find : values of p+q+r and   pqr.

Solution:

cubic polynomial x³ – 6 x² – x + 30  

p, q, r are the zeroes

Sum of zeroes  =  - ( - 6) / 1  = 6

Hence p + q + r = 6

Product of zeroes  =     -30/ 1 = -30

=> pqr =   -30

Another method :

x³ – 6 x² – x + 30  

= (x - 3)(x²  - 3x  - 10)

= (x - 3)(x - 5)(x + 2)

p , q and r  are    - 2 ,  3 ,  5  

p + q + r = - 2 + 3 + 5 = 6

pqr = (-2)(3)(5)  = - 30

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