Question

if p,q,r are three prime number such that p²+q²=r then find value of p,q,r​

Answer 1

Answer:

Step-by-step explanation:

If p and q are both odd, then r=pq−1 is even so r=2.

But in this case pq ≥  3 × 3 = 9 and hence there are no solutions.

This proves that either p=2 or q=2. If p=2 then we have 2q=r+1 and 8+2q  ^2  =r  ^2 +1.  

Multiplying the second equation by 2 we get 2r  ^2  + 2 = 16 + (2q)  ^2  = 16 + (r + q)  ^2 .  

Rearranging the terms, we have r  ^2

−2r−15=0, or equivalently (r+3)(r−5)=0.

This proves that r=5 and hence q=3.

Similarly if q=2 then r=5 and p=3.

∴(p,q,r)=(2,3,5) and (p,q,r)=(3,2,5).

Answer 2

Answer:

my self mantasha Fathima who is Aryan

and iam 12 years old

not 14

iam in 10th class

aap. kou galt fahmi hou hai