If p,q,r are zeroes of p(x)=9x³-3x²-7x+1, then find the value of p-1 +q-1 +r-1
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The cubic polynomial is 9x³ - 3x² - 7x + 1 and p, q, and r are the zeros of the equation. Therefore, if 9x³ - 3x² - 7x + 1 = 0, then x = p, x = q and x = r will be the roots of the equation. Using vanishing method x = 1 makes the equation valid. Hence, (x - 1) will be a factor of the expression
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