Question

if p,q,r in arithmetic progration and x,y,z in geomatric progration then x^q-r × y^r-p × z^p-q is equal to..........​

Answer 1

Answer:

Here is your answer:

p,q,r are in AP so 2q = p+r

and x,y,z are in gp so y² = xz

Now x^q-r y^r-p z^p-q = x^(p+r/2-r) y^r-p z^(p-(p-r)/2)

= x^(p-r/2) . y^r-p z^(p-r/2)

= x^(p-r/2) . (xz)^(r-p)/2 z^(p-r/2)

= x^(p-r/2) . x^(r-p/2) z^(r-p/2) z^(p-r/2)

= x^0 z^0

= 1

If there is any confusion please leave a comment below.

Step-by-step explanation:

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