If P Q R S is a kite and <SPQ = 40
Then find PSQ and PQS
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Opposite angles of a parallelogram are equal
∴∠SPQ=∠SRQ=70
o
In △SQR,∠RSQ+∠SQR+∠SRQ=180
o
∠RSQ=180−60−70
RSQ=50
o
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