If p,q,r terms of an A.P. are x,y,z respectively . prove that
x(q-r)+y(r-p)+z(p-q)=0
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Answer:
x=a+(p-1)d
y=a+(q-1)d
z=a+(r-1)d
y-z=(q-r)d
q-r = (y-z)/d
x(q-r)=x(y-z)/d......(1)
Similarly
y(r-p)=y(z-x)/d.....(2)
z(p-q) = z(x-y)/d.....(3)
Add (1) + (2) +(3) you will get
x(q-r) + y(r-p) +z(p-q)= (xy-xz +yz-yx+zx-zy)/d=0
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