If (P+q)th term of an AP is m and (P+q)th term is n, then pth term is?
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Answer:
a+(p+q-1)d=m
a+(p-q-1)d=n
subtracting both the equations we get
a-a+(p+q-1-p+q+1)d=m-n
0+(2q)d=m-n
d=(m-n)/2q
puting this value in the first equation we get
a+(p+q-1)(m-n)/2q=m
a+(p-1)(m-n)/2q + q(m-n)/2q =m
therefore a+(p-1)d +(m-n)/2 =m
so a+(p-1)d =m-(m-n)/2
=(2m-m+n)2
a+(p-1)d =(m+n)/2
Since a+(p-1)d is the form of the pth term therefore,
pth term = (m+n)/2
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