if P represents radiation pressure , c represents speed of light and Q represents radiation energy striking a unit per second , then non-zero integers x,y and z are such that PxQyCz is dimensionless.x,y,z are the powers of P,Q,C respectively.
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Thanks for asking the question.
ANSWER::
Question is from the chapter Unit And Dimensions of Class 11
Dimensions of Radiation Pressure = M1L-1T-2
Dimensions of Speed of Light = M0L1T-1
......
and the answer continues in the picture please refer that.
Hope it helps!
ANSWER::
Question is from the chapter Unit And Dimensions of Class 11
Dimensions of Radiation Pressure = M1L-1T-2
Dimensions of Speed of Light = M0L1T-1
......
and the answer continues in the picture please refer that.
Hope it helps!
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Answered by
99
Answer:
Explanation:
Let k=PxSycz .....(i)
k is a dimensionless
Dimensions of k=[M0L0T0]
∴ Dimensions of P =ForceArea=[MLT−2][L2]=[ML−1T−2]
Dimensions of S= EnergyArea× time=[ML2T−2][L2][T]=[MT−3]
Dimensions of c=[LT−1]
Substituting these dimensions in eqn (i), we get
[M0L0T0]=[ML−1T−2]x[MT−3]y[LT−1]z.
Applying the principle of homogeneity of dimensions, we get
x+y=0 ....(ii)
−x+z=0 ....(iii)
−2x−3y−z=0 ....(iv)
Solving (ii), (iii) and (iv), we get
x=1,y=−1,z=1
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