Question

if p= rs.1000,r=6%p.a , n=3 years. Find amount and compound interest.​

Answer 1

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Principle = Rs. 1000
• Rate = 6%
• Time = 3years

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• Amount = ??
• Simple Interest = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

$\sf{\red{\boxed{\bold{Amount = Principle\bigg( 1 + \dfrac{r}{100}\bigg)^t}}}}$

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$\sf: \implies\: {\bold{ Amount = 1000\bigg( 1 +\dfrac{6}{100}\bigg)^3}}$

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$\sf: \implies\: {\bold{ Amount = 1000\bigg( \dfrac{100 + 6}{100}\bigg)^3}}$

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$\sf: \implies\: {\bold{ Amount = 1000\bigg( \dfrac{106}{100}\bigg)^3}}$

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$\sf: \implies\: {\bold{ Amount = 1000\times \dfrac{106\times106\times 106}{100\times 100\times 100}}}$

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$\sf: \implies\: {\bold{ Amount = 10\times \dfrac{106\times106\times 106}{100\times 100}}}$

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$\sf: \implies\: {\bold{ Amount = 1\times \dfrac{106\times106\times 106}{100\times 10}}}$

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$\sf: \implies\: {\bold{ Amount = \dfrac{106\times106\times 106}{100\times 10}}}$

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$\sf: \implies\: {\bold{ Amount = \dfrac{106\times11236}{1000}}}$

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$\sf: \implies\: {\bold{ Amount = \dfrac{1191016}{1000}}}$

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$\sf: \implies\: {\bold{ Amount = Rs. 1191. 016 }}$

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$\sf: \implies\: {\bold{ Amount = Rs. 1191. 02 }}$

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$\sf{\red{\boxed{\bold{CI = Amount - Principle }}}}$

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$\sf: \implies\: {\bold{ CI = Rs. 1191. 02 - Rs. 1000}}$

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$\sf: \implies\: {\bold{ CI = Rs. 191.02 }}$

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Rs. 1000 will amount to Rs. 1191.02 with Rs. 191.02 as CI in 3 years at 6% per annum.