Question

if p=secA+tanA then prove that sinA=(p2-1)/(p2+1)

Answer 1

p=secA+tanA

p=1/cosA+sinA/cosA

p=1+sinA/cosA

P^2=(1+sinA)^2/(1+sinA)(1-sinA)

P^2=1+sinA/1-sinA

p^2-p^2.sinA-1=sinA

p^2-1=(p^2+1)(sinA)

p^2-1/p^2+1=sinA

Answer 2

Answer:

your answer attached in the photo